Question

Find the sum of all natural numbers less than 100 which are divisible by 6 ? *

1 point

816

900

1500​

Answer 1

Step-by-step explanation:

6,12,18,...96 are all natural less than 100 and divisible by 6

first term =6

common difference= d = a2 -a1=12-6 =6

nth term = 96

a+(n-1)d=96

6+(n-1)6=96

(n-1)6=96-6

(n-1)6=90

n-1=90/6

n-1=15

n=15+1

n=16

sum = n/2[a+ nth term]

=16/2[6+96]

=8×102

=816

Answer 2

Answer:

ANSWER IS 816.

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