Find the sum of all natural numbers less than 100 which are divisible by 6?
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Answered by
9
Following are the natural numbers divisible by 6-
6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96
and their sum is 816
6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96
and their sum is 816
Answered by
15
a=6
d=6
l=An=96
An=a+(n-1)d
96= 6+(n-1)6
96=6+6n-6
96=6n
n=96/6
n=16
Sn=n/2*(a+l)
Sn=16/2*(6+96)
Sn=8*102
Sn=816
therefore the sum of the multiples of 6 till 100 is 816
d=6
l=An=96
An=a+(n-1)d
96= 6+(n-1)6
96=6+6n-6
96=6n
n=96/6
n=16
Sn=n/2*(a+l)
Sn=16/2*(6+96)
Sn=8*102
Sn=816
therefore the sum of the multiples of 6 till 100 is 816
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