Math, asked by hardiknarain2236, 1 year ago

find the sum of all natural numbers lying between 100 and 1000which are multiples of 5.

Answers

Answered by brilliant68

3

Step-by-step explanation:

100+105+200+205+300+305+400+405+500+505+600+605+700+705+800+805+900+905+100: 3610

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