Math, asked by vijirenjusree8961, 10 months ago

Find the sum of all natural numbers lying between 100 and 500 which is divis8ble by 8.

Answers

Answered by haridasan85

0

8).100,500

13,62

no. of terms n=62-12 = 49

Progression =104,112,120,128......

S49=n/2{2a+(n-1) xd}

= 49/2{2x49+(49-1) x8}

= 49/2{98 +48x8}

= 49/2{98+384 }

= 49/2x482

= 49x241 =11809

Answered by KJB811217

3

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