Political Science, asked by neelamgupta737, 7 months ago

find the sum of all natural numbers lying between 250 and 1000 which are diversible by 9​

Answers

Answered by anilsingh280
0

Answer:

750

the correct answer

Answered by udayranjan80
1

Answer:

52542

Explanation:

252+261+270+..........+999

a=252,d=9,Tn=999

Tn =a+(n-1)d

999=252+(n-1)9

999 =252+9n-9

9n=999-243

9n=756

n=756/9

n=84

Sn=n/2(2a+(n-1)d

=84/2(2×252+(84-1)9)

=42(504+747)

=42×1251

=52542

Similar questions