Question

Find the sum of all numbers between 1 to 100 which are divisible by 4.With solution..

Answer 1

Heya mate,Here is ur answer

a(first term) = 4 ( 4×1=4)

an(last term)= 100 (4×25=100)

n(total terms) = 100/4

n=25

$sn = \frac{n}{2} (a + an)$


$sn = \frac{25}{2} (100 + 4)$


$sn = \frac{25}{2} \times 104$


$sn = 25 \times 52$


$sn = 1300$

$<b><u>So, sum of all number divided by 4 b/w 1 to 100 is 1300.</b></u>$

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@Laughterqueen

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Answer 2

Hey !!

Numbers which are divisible by 4 between 1 to 100 are : 4 , 8 , 12 , ..........., 100.

AP = 4 , 8 , 12 , ......................, 100

Here,

First term ( a ) = 4

Common difference ( d ) = 8 - 4 = 4

Last term ( Tn ) = 100

a + ( n - 1 ) d = 100

4 + ( n - 1 ) × 4 = 100

4 + 4n - 4 = 100

4n = 100

n = 25

Sn = n/2 × [ First term + Last term ]


S25 = 25/2 × [ 4 + 100 ]




=> 25/2 × 104


=> 25 × 52



=> 1300.

Hence,

The sum of numbers which are divisible by 4 between 1 to 100 is 1300.