Question

find the sum of all numbers between 100 and 200 which are divisible by 15​

Answer 1

Answer:

1050

Step-by-step explanation:

first term =105

last term =195

common difference=15

total no. of terms ,n= l-a/d +1

=195-105/15+1

=7

Sum of the terms = n/2 [2a +(n-1) d]

=1050

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Answer 2

Answer:

1050

Step-by-step explanation:

first term =195

second term=105

difference=15

no. of terms= 195-105÷15+1

no. of term= 7

sum of term =1050