Question

Find the sum of all numbers between 100 and 750 leaves remainder 4 when divided by 7.​

Answer 1

Answer:

Given,

The series of numbers between 100 and 300, when divided by 3 and leaving the remainder 2 is,

101,104,107,............,299

a.

first number =101

b.

last number =299

c.

a

n

=a+(n−1)d

299=101+(n−1)3

n−1=

3

198

=66

Total numbers ∴n=67

S

n

=

2

n

[a+l]

=

2

67

[101+299]

=

2

67

[400]

=13400

Step-by-step explanation:

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