find the sum of
all numbers
between 6oo and 800 divisible
by 7
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UU Umari I have to go to the gym and then
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First since 7 & 9 are relatively prime numbers, their common multiples are 63n ….So for now to find n, 600 ≤63n≤800,. Solving for n you get 9.5≤n≤12.7,. So, since n is integer the values for n are 10,11&12…And the multiples are 63(10)=630, 63(11)=693 & 63(12)=756,. But, The only number is 693 whose digits' sum is 18
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