Math, asked by justoocute, 10 months ago

Find the sum of all numbers lying between 50 and 300 divisible by 6.

Answers

Answered by udaykumar92
1

n(n+1)/2

=300(300+1)/2

=9000+300/2

=9300/2

=4650

n(n+1)=50(50+1)=2500+50=2550

4650-2550=2400

2400 is divisible by6 =400

Answered by KJB811217
2

Answer:

refers to the attachment

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