Find the sum of all numbers lying between 50 and 300 divisible by 6.
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n(n+1)/2
=300(300+1)/2
=9000+300/2
=9300/2
=4650
n(n+1)=50(50+1)=2500+50=2550
4650-2550=2400
2400 is divisible by6 =400
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