find the sum of all numbers that give remainder 2 on dividing by 11 and lying between 250 and 600 .full solution
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In AP
first no = 252 and last number is 999 which divisible by 3
let total no be n
so
999=252+(n-1)3 (By using AP)
n=250
By using Sn=(n/2){2a+(n-1)d}
solve
then 156375
first no = 252 and last number is 999 which divisible by 3
let total no be n
so
999=252+(n-1)3 (By using AP)
n=250
By using Sn=(n/2){2a+(n-1)d}
solve
then 156375
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