Question

find the sum of all numbers which leaves the remainder 5 and divided by 7 between 50 and 200​

Answer 1

Answer:

200

Step-by-step explanation:

7÷200=remainder 5

Answer 2

Answer:

2550

Step-by-step explanation:

The numbers are 61,68,75,.....194.

This series is an ap having first term(a)=6l, common difference (d) = 7.

As we know 194 is the last term (l).

l= a + (n-1) d

194= 61+(n-1)7

194-61=(n-1)7

133=(n-1)7

133/7=(n-1)

19=(n-1)

n=20

This means that there are 20 elements in this AP.

sum=n/2(2a+(n-1)d)

sum=20/2(2*61+(20-1)7)

sum=10(122+19*7)

sum=10(122+133)

sum=10*255

sum=2550