Question

Find the sum of all odd integen
between 2 and 100 divisible by 3.​

Answer 1

Answer:

I hope it will helpful to you

Answer 2

3+6+9+…+99 (series 1)

These are all the integers between 2 and 100 which are multiple of three.

6+12+18+…+96 (series 2)

These are all the integers between 2 and 100 which are multiple of 3 and are even.

Therefore sum of all the odd intergers between 2 and 100 divisible by 3 is nothing but sum of series 1 minus the sum of series 2.

Now number of terms in series 1 is 33 therefore the sum would become 1683.

In the second series number of terms is 16 therefore the sum would become 816.

Therefore the answer should be = 1683 - 816 = 867.

Or u can just take the series-

3+9+15+…+99

And find it's sum which should also give you 867.