Find the sum of all odd integers between 2 & 100 divisible by 3.
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Find the sum of all odd integers between 2 & 100 divisible by 3.
Good question,
Here is your perfect answer!
Odd integers btw 2&100 are 3,9,15,21...99.
Here d= 6.
To find n,
=) an = a + (n-1)6
=) 99 = 3 + (n-1)6
=) 99-3 = (n-1)6
=) 96/6 = n-1
=) 16 = n-1
=) 17 = n
Since Sn = n/2 (a + l)
S17 = 17/2 * (3+99)
= 17/2 * 102
= 17* 51
= 867.
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Hi mate
Here is your answer
Plz refer to the attachment
Hope it helps
BE BRAINLY////
Here is your answer
Plz refer to the attachment
Hope it helps
BE BRAINLY////
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