Question

find the sum of all odd integers between 2 and 100 divisible by 3 ?
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Answer 1

ANSWERS

The odd integers between 2 and 100 which are divisible by 3 are 3, 9, 15, 21, ..., 99. Here, a = 3 a=3 a=3 and d = 6 d=6 d=6

Answer 2

Step-by-step explanation:

first number = 3 ,common difference = 3

last number = 99

in ap Sn=n\2(a+ l)

TN =a+( n-1)d

99=3+(n-1)3

96= 3n-3

93= 3n

n=31

now,Sn=31/2(3+99)

=31×102/2

=51×31

=. 1581