Find the sum of all odd integers between 300 and 498
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Answered by
4
hi my
here's your answer
Step-by-step explanation:
number of odd integers between 300 and 497=(497-301)/2=98
Therefore, number of odd integers between 300 and 498 = 98+1 = 99
Sum of Arithmetic progressions = ,n/2(a+l) where 'a' is the first term and 'l' is the last term.
Sum of odd integers between 300 to 498
= 99/2(301+497)=39501.
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Answered by
4
Answer:
39501
Step-by-step explanation:
Here is your answer
the numbers are
301 , 303 , …. 497
497 = 301 + (n-1)2
2n = 198
n= 99
Sum = 99/2 (301 + 497)
= 99*399 = 39501
Hope you liked the solution. please mark me as brainliest
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