find the sum of all odd natural from 50 to 550
Answers
Answered by
0
Step-by-step explanation:
Given,
First term = 50
Last term = 550
To find = Sum of all odd numbers
Number of terms between 50 and 550 = 550 - 50 - 1
= 499
Number of odd terms = (499+1)/2
= 250
Common difference between two odd numbers = 2
Sum = 250÷2 × (2×51 + (250-1)×2)
= 125 × (102 + 498)
= 125 × 600
= 75,000
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Answered by
0
Step-by-step explanation:
s= (n/2)(a+l)
a(nth)= a+(n-1)d
449= 51+(n-1)2
449-51=2n-2
398=2n-2
2n=400
n=200
so s=(200/2)51+449
s= 100×500
=50000
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