find the sum of all odd natural numbers from 1to150
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Answered by
3
The odd numbers btw 1 and 150 are
1,3,5,7,9,..................,149
Now,in this AP a=1, d=2, n=75
Sn= n/2(2a+(n-1)d)
=75/2(2×1(75-1)2))
=75/2(2(74×2)
=11100
Hence,the sum of the odd numbers is 11100
THANKS!
1,3,5,7,9,..................,149
Now,in this AP a=1, d=2, n=75
Sn= n/2(2a+(n-1)d)
=75/2(2×1(75-1)2))
=75/2(2(74×2)
=11100
Hence,the sum of the odd numbers is 11100
THANKS!
InsaneJaat:
please mark the answer as brainliest if you like it
Excuse me your answer is wrong
D=2 not 1
okk
i have corrected it
Answered by
8
Ap= 1,3,5,7...149
We know that,
N=an-a/d +1
149-1/2 + 1
74+1
N=75
We also know that,
Sn=n/2(a+an)
75/2(1+149)
75/2 ×150
Sn=5625
We know that,
N=an-a/d +1
149-1/2 + 1
74+1
N=75
We also know that,
Sn=n/2(a+an)
75/2(1+149)
75/2 ×150
Sn=5625
Mark it as brainless
Brainless**
Sorry autocorrect
I meant brainliest**
you are a funny guy bro
Why did u report me.when I helped you with your mistake
sorry brother
Your one of the reason why there is no hope for humanity in this world but whatever
okk its my fault i am really so sorry
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