find the sum of all odd numbers divisible by 3 between 1 and 1000
Please solve this
Today is my exam
Answers
Answered by
2
sum=n/2(a+l)
1,3,5,7,9,11...........999
nth term in 999, thus
an=a+(n-1)d
99=1+(n-1)2
99=1+2n-2
99=2n-1
99+1=2n
100=2n
n=50
Sn=n/2(a+l)
=50/2(1+99)
= 25(100)
=2500(answer)
1,3,5,7,9,11...........999
nth term in 999, thus
an=a+(n-1)d
99=1+(n-1)2
99=1+2n-2
99=2n-1
99+1=2n
100=2n
n=50
Sn=n/2(a+l)
=50/2(1+99)
= 25(100)
=2500(answer)
Similar questions