Math, asked by jeremysamuelnewton, 10 months ago

Find the sum of all odd positive integers less than 450.

Answers

Answered by aks252006
0

Answer:

For solving this you have to form an ap

Step-by-step explanation:

AP- 1,3,5,7,9,11..........,449

A=1 cd=3-1=2 an=449

an = a+(n-1)d

449=1+(n-1)2

449-1=(n-1)2

448/2=(n-1)

224=(n-1)

224-1=n

223=n

Sn=n/2(a+an)

S223=223/2(1+449)

S223=223/2*450

S223=223*225

S223=50175

Hence the sum of all odd positive integers less than 450 is 50175

Step-by-step explanation:

Answered by jayantypradan
1

Answer:

For solving this you have to form an ap

Step-by-step explanation:

AP- 1,3,5,7,9,11..........,449

A=1 cd=3-1=2 an=449

an = a+(n-1)d

449=1+(n-1)2

449-1=(n-1)2

448/2=(n-1)

224=(n-1)

224-1=n

223=n

Sn=n/2(a+an)

S223=223/2(1+449)

S223=223/2*450

S223=223*225

S223=50175

Hence the sum of all odd positive integers less than 450 is 50175.

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