Math, asked by pandagotskills, 11 months ago

Find the sum of all positive integers less than 100, which are not divisible by 3.

Answer please

Answers

Answered by ERB
2

Answer:

3267

Step-by-step explanation:

sum of integers not divisible by 3= sum of all integers - sum of integers                             divisible by 3

=(1+2+3+4+5+............................99) - (3+6+9+..................99)

=(99*100)/2 - (33/2)(3+99)       here,  n=33

=4950 - 1683

=3267

Answered by FelisFelis
2

The required answer is 3267.

Step-by-step explanation:

Consider the provided information.

First find the sum of all positive integers less than 100.

1, 2, 3, 4,....99

Find the total number of terms by using the formula: a_n=a+(n-1)d

Substitute a=1, aₙ=99 and d=1 in above formula.

99=1+(n-1)1\\98=n-1\\n=99

To calculate the sum use the formula: S_n=\frac{n}{2}[2a+(n-1)d]

Substitute the respective values in the above formula.

S_n=\frac{99}{2}[2(1)+(99-1)(1)]

S_n=\frac{99}{2}[2+98]\\S_n=50\times99\\s_n=4950

Now the number divisible by 3 are 3,6,9,...99

Find the number of terms.

a_n=a+(n-1)d\\99=3+(n-1)3\\\frac{96}{3}=n-1\\n=33

Now calculate the sum.

S_n=\frac{33}{2}[2(3)+(33-1)(3)]\\S_n=\frac{33}{2}[6+96]\\S_n=51 \times33\\S_n=1683

Now subtract the sum of all positive integers less than 100 and divisible by 3 with sum of all positive integers less than 100.

4950-1683=3267

Hence, the required answer is 3267.

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