Find the sum of all possible 3- digits numbers which can be formed by the digits 4,6 and 8 where the repetition of the digits is not allowed ?
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How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming that.
i) Repetition of the digits is allowed?
ii) Repetition of the digits is not allowed?
November 22, 2019avatar
Sherry Sao
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ANSWER
1)
A three digit number is to be formed from given 5 digits 1,2,3,4,5.
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HTO
Now, there are 5 ways to fill ones place.
Since, repetition is allowed , so tens place can also be filled by 5 ways.
Similarly,hundreds place can also be filled by 5 ways.
So, number of ways in which three digit numbers can be formed from the given digits is 5×5×5=125
Alternative Method:
There will be as many way ways as there are ways of filling 3 vacant places in succession by the given five digits. In this case, repetition of digits is allowed. Therefore, the units place can be filed by any of the given 5 digits.
Similarly, tens and hundreds digits can be filled in by any given 5 digits.
Thus, by the multiplication principle, the number of ways in which three digit numbers can be formed from the given digits is 5×5×5=125
ii) A three digit number is to be formed from given 5 digits 1,2,3,4,5.
□□□
HTO
Now, there are 5 ways to fill ones place.
Since, repetition is not allowed , so tens place can be filled by remaining 4 digits.
So, tens place can be filled in 4 ways.
Similarly, to fill hundreds place, we have 3 digits remaining.
So,hundreds can be filled by 3 ways.
So, required number of ways in which three digit numbers can be formed from the given digits is 5×4×3=60
Answer:
the possible 3 digit number