Question

Find the sum of all such multiples of 7 which are less than 500.
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Answer 1

Answer:

Answer is easy...give it a try by yourself

Step-by-step explanation:

exam is coming..

Answer 2

Answer:

Step-by-step explanation:

Let the multiples of 7 less than 500 be the A.P: 7,14,21.....497

Here, 1st term (a) = 7

Common difference (d) = 14 -7 = 7

Last term (l) = 497

So, l = a+(n-1)d

497 = 7+(n-1) × 7

497- 7 = (n-1) × 7

490/7 = n-1

70 = n-1

n=70+1 = 71

Now, Sn = n/2(a + l)

= 71/2 (7 + 497)

= 71/2 × 504

= 71×252

= 17892

Hence the required sum is 17892