Find the sum of all the 11 terms of an A.P. whose middle most term is 30.
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We are given total number of terms in ap are 11 terms and middle term is 30
So middle term = 11+1/2 = 6th term
A6 = a + 5d = 30
a = 30-5d
S11 = 11/2(2a+10d)
= 11(a+5d)
= 11(30-5d+5d)
= 330
So middle term = 11+1/2 = 6th term
A6 = a + 5d = 30
a = 30-5d
S11 = 11/2(2a+10d)
= 11(a+5d)
= 11(30-5d+5d)
= 330
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