Question

Find the sum of all the 11 terms of an AP whose middle most term 30.

Answer 1

Answer:

hope it will help u and plz mark me as good and follow me

Answer 2

Answer:

   Sn =330

Step-by-step explanation:

Given middle term or the sixth term is 30  

As we know, an =a+(n−1)d, where a & d are the first term and common difference of an AP respectively.

Then, a+5d=30

Sum =    n/2 (2a+(n−1)d)

      S11  =  11/2 (2a+10d)

Substituting,

=  11/2  (2×30)

=330

PLEASE MARK ME AS BRAINIST