Question

Find the sum of all the 11 terms of an AP whose middle most term is 30.

Answer 1

Here is your answer

Answer 2

it's a tricky question yet let us try to solve
Ok first of all
We can say that 30 is the Median of 11 terms.
therefore
we know
M = (n + 1)/2 th observation for n = odd
Therefore the 6th term of this AP is 30
Therefore A6 = 30
a + 5d = 30

therefore we need to find S11
Therefore S11 = n/2(2a + (n-1)d)
=11/2(2a + 10d)
=11/2(2(a + 5d)
replacing value
=11/2(2(30))
=11 * 30
=330
therefore Answer is 330