Find the sum of all the first ‘n’ odd natural numbers.
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Answer:
DaMEn It...I think So
Step-by-step explanation:
A.P(Arithmetic Progression), the sum of numbers is given by,
Sn=1/2×n[2a+(n-1)×d]
Where,
Sn= Sum of n numbers
n = n numbers
a = First term of an A.P
d= Common difference in an A.P
But, to find the sum of n odd numbers, there is a quick formulae,
Sn(odd numbers)= n²
For instance, what is the sum of first 10 odd numbers??
Here, n=10
Therefore, Sn=n²
Sn = 10²
Sn=100
Hope that helps!!
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Regards,
SHAKA BRO
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