Question

find the sum of all the integers between 1 to 50 which are nit divisible by 3​

Answer 1

Step-by-step explanation:

the sum of all the inteeger between 1 and 50

1+50/3

51/3

17 is your answer

Answer 2

Answer:

The no.s between 1 n 50 divisible by 3 are:

3,6,9,12......48

These no.s are clearly in an AP, where,

a=3

d=3

Let 48 be nth term of the AP

so,

a+(n-1)d=48

=>3+(n-1)3=48

=>3(1+n-1)=3×16

=>n=16

Now,

S16=16 {a+l}

2

=8(3+48)

=8×51

=408

So, the sum of all the integers b/w 1 n 50 is 408