Question

Find the sum of all the integers between 100 and 400 which are divisible by 6

Answer 1

By using AP,

we know the first no. between 100 and 400 which is divisible by 6 is 102 and last no. is 396

so, position of 396= 102+(n-1)6

here we get n as 50

Therefore there are 50 numbers between 100 and 400 divisible by 6.

Now, sum is given by ((102+396)*50)/2 which is equal to 12450

Answer 2

12450




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