Find the sum of all the integers from 100 to 200 inclusive(using formula of arithmetic progression sum)
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6
15150 is the answer for the question
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happy new year.
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Ap: 100,101,102.........200
a=100
an=200
D=1
an=a+(n-1)d
200=100+(n-1)1
200-100=n-1
100=n-1
n=101
S101=n/2(a+an)
= 101/2(100+200)
=101/2×300
=15150
a=100
an=200
D=1
an=a+(n-1)d
200=100+(n-1)1
200-100=n-1
100=n-1
n=101
S101=n/2(a+an)
= 101/2(100+200)
=101/2×300
=15150
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