Find the sum of all the multiples of 2 or 3 between 100 and 200.
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first multiples of 2
a=102 and Tn=198
n=48
s48= 48/2[2*102+47*2]
= 24(204+94)
24(298)
a=102 and Tn=198
n=48
s48= 48/2[2*102+47*2]
= 24(204+94)
24(298)
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Hope this s gonna help u
I'm not sure if the answer actually
I'm not sure if the answer actually
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S this correct
Pls mark me as brainliest
was that the end of it??
Ya Caz 49 numbers are there
N sum s already found
Mark as brainliest
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