Question

find the sum of all the natural number between 300 and 900 which are the multiple of 11​

Answer 1

I have written it by myself please mark it as the brainllist if it will help you please say thanks for this answer too. . . . .

Answer 2

a1=308

an=891

d=11

an=a+(n-1)d

891=308+(n-1)11

891=308+11n-11

891=297+11n

594=11n

n=594/11=54

Sn=n/2(a+an)

Sn=54/2(308+891)

Sn=27(1199)

Sn=32373