Question

Find the sum of all the natural numbers between 1 to 200 which are multiples of 5​

Answer 1

Answer:

solution:

to find: sum of all the multiples between 1 to 200,which are multiples of 5

∴a=5a=5 ,

∴d=5d=5 ,

∴a_n=200a

n

=200

a_n=a+(n-1)da

n

=a+(n−1)d

200=5+(n-1)5200=5+(n−1)5

200-5=(n-1)5200−5=(n−1)5

195=(n-1)5195=(n−1)5

195/5=n-1195/5=n−1

39=n-139=n−1

∴ n=40n=40

S_n=n(a+l)/2S

n

=n(a+l)/2

S_{40}=40(5+200)/2S

40

=40(5+200)/2

S_{40}=20(205)S

40

=20(205)

∴S_{40}=4010S

40

=4010

∴The sum of all the natural numbers between 1 to 200, which are multiples of 5 is 4010

Answer 2

Answer:

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