Find the sum of all the natural numbers between 100 and 200, which are multiples of 5.
Answers
Answered by
0
Answer:
Between 100 to 200 First number -102; last number -198
Total number are
=lastno.−firstno.diff.+1=198−1023+1
=963+1=33
sum=n2[2a+(n−1)d]
=332[2×102+(33−1)×3]
=332[204+96]
=33×150=4950
Similar questions