Question

Find the sum of all the natural numbers between 100 and 500 which are divisible by 4.


step by step answer​

Answer 1

Answer:

Hence, the sum of all numbers lying between 100 and 500 and divisible by 8 is 15000.

Step-by-step explanation:

104, 112, 120, 128, 136,…, 496 a2 – a1 = 112 – 104 = 8 a3 – a2 = 120 – 112 = 8 ∵ a3 – a2 = a2 – a1 = 8 Therefore, the series is in AP Here, a = 120, d = 8 and an = 496 We know that, an = a + (n – 1)d ⇒ 496 = 104 + (n – 1)8 ⇒ 496 – 104 = (n – 1)8 ⇒ 392 = (n – 1)8 ⇒ 49 = (n – 1) ⇒ n = 50 Now, we have to find the sum of this AP ⇒ S50 = 25[208 + 49 × 8] ⇒ S50 = 25[600] ⇒ S50 = 15000Read more on Sarthaks.com - https://www.sarthaks.com/952143/find-the-sum-of-all-natural-numbers-lying-between-100-and-500-which-are-divisible-by-8