Find the sum of all the natural numbers less than 100 which are divisible by 6
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Natural numbers less than 100 and divisible by 6:
6, 12, 18, 24, ... 96
This forms an AP with 'a' = 6 and 'd' = 6, 'aₙ' = 96
⇒ aₙ = a + ( n - 1 ) d
⇒ 96 = 6 + ( n - 1 ) 6
⇒ 96 - 6 = ( n - 1 ) 6
⇒ 90 = ( n - 1 ) 6
⇒ 90/6 = ( n - 1 )
⇒ 15 = n - 1
⇒ n = 15 + 1 = 16 terms
Sum of 'n' terms of an AP:
⇒ Sₙ = n/2 [ a + aₙ ]
⇒ S₁₆ = 16/2 [ 6 + 96 ]
⇒ S₁₆ = 8 ( 102 )
⇒ S₁₆ = 816
Therefore,
sum of all natural numbers less than 100 which are divisible by 6 is
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