Find the sum of all the numbers between 0 and 207 which are exactly
numbers between 0 and 207 which are exactly divisible by 3.
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Answer:
numbers between 0 to 207 divisible by 3 will be 3,6,9,12,15.....204
common difference =3
t1 =3
t2=6
tn=204
Step-by-step explanation:
to find : n
tn=a + [(n-1)d]
204=3+(n-1) 3
204-3= 3n- 3
201=3n-3
201+3=3n
204=3n
n=204/3
n =68
As we know
Sn=n/2(t1+tn)
Sn=68/2(3+204)
34(207)
7038
therefore the sum of numbers between 0 to 207 divisible by 3 is 7038
hope this helps!!!
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