Find the sum of all the three digit number which are divisible by 9
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Answered by
10
Answer:
55350
Step-by-step explanation:
108+117+126.................+999
a=108 d=9 l=999
l=a+(n-1)d
999 =108+(n-1)×9
999=108+9n-9
999-99=9n
900=9n
n=100
S=n/2(a+l)
S=100/2 (108+999)
S=50×1107 =55350
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