find the sum of all the three digit numbers which are divisible by 91
Answers
Answered by
0
Step-by-step explanation:
Smallest 3 digit natural number divisible by 3=102
Largest 3 digit natural number divisible by 3=999
∴3 digit number divisible by 3 are:
102,105,108,.....999
this is an AP with a=102 and d=3
no.of terms
999=a+(n−1)d
999=102+(n−1)3
3
897
=(n−−)⇒(n−1)=299
∴n=300
Sum of all numbers = Sum of 300 terms of AP
=
2
300
[2a+)300−1)d]
=
2
300
[2×(102)+(299)3]
=(150)[204+891]
Sum of all number of series =(150)[1101]=165150
∴ Sum of all 3 digit number divisible by 3 is 165150
PLZZ.make as brainliest
Answered by
1
Answer:
182 + 273 + 364 + 455 + 546 +637 + 728 +819 + 910
These are all three digit nos. divisible by 91.......
Please sum it urself.....
Similar questions
Social Sciences,
5 months ago
Math,
5 months ago
Computer Science,
10 months ago
Hindi,
10 months ago
Math,
1 year ago