Question

find the sum of all the two dight numbers which leave the remainder two when divided by 5

Answer 1

Answer:

Step-by-step explanation:

5+2=7

10+2=12

15+2=17

20+2=22

25+2=27

30+2=32

35+2=37

40+2=42

45+2=47

50+2=52

55+2=57

60+2=62

65+2=67

70+2=72

75+2=77

80+2=82

85+2=87

90+2=92

95+2=97

7+12+17+22+27+32+37+42+47+52+57+62+67+72+77+82+87+92+97=988

Answer=988