find the sum of all the two digit numbers which leave the remainder 2 when divided by 5
Answers
Answered by
6
Answer:
Step-by-step explanation:
A.P = 12,17,22.......97
A=12
D=5
An=a+n-1d
97=12+n-1d
85/5=n-1
N=17+1=18
S18=18/2×2×12+17×5
9×24+85
9×109
981
Similar questions