Math, asked by ckishoreramana5215, 11 months ago

Find The Sum Of All Three Digit Natural Numbers Which Are Multiples Of 13

Answers

Answered by Bhaavinjain
1

Answer:

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Sum of all 3-digit natural numbers, which are divisible by 13 = 37674

Step-by-step explanation:

The sum of 3-digit number between 100 and 999 that are divisible by 13 can be found out by arithmetic sum i.e.

First 3-digit number that is divided by 13 is 104

Greatest 3-digit number that is divided by 13 is 988

Formula for the sum of Arithmetic progression is   with “a” being the value of the first number of the series and “l” being the last.

Therefore, a = 104 and l = 988

Value of n depends on the larger number which is divisible by 13 that is 988 by 13 is 76, whereas the number 104 divided by 13 is 8, so the number of terms is 76 – 13 = 69

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