Find the sum of all three-digit natural numbers, which on being divided by 5, leave a remainder equal to 4.
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Answer:
see in the Google ok
plzz
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Step-by-step explanation:
let the three natural numbers be A,B,C
A+B+C
-------------- =4 [given in question]
5
so, A+B+C=4×5
A+ B+C = 20
hope it helps... ...
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