Math, asked by shamsmohammed3755, 9 months ago

Find the sum of all three-digit natural numbers, which on being divided by 5, leave a remainder equal to 4.

Answers

Answered by darkwizard81
0

Answer:

see in the Google ok

plzz

Answered by kaviya677
0

Step-by-step explanation:

let the three natural numbers be A,B,C

A+B+C

-------------- =4 [given in question]

5

so, A+B+C=4×5

A+ B+C = 20

hope it helps... ...

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