Find the sum of all three digit natural numbers which on division by 7 remainder
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The smallest 3 digit number = 100
The first 3 digit number is also 100.
To find the first 3 digit number divisible by 7, we divide the very first 3 digit number 100 by 7
100/7 = 14.29
We have decimal in the result of 100/7.
Clearly the first 3 digit number 100 is not exactly divisible by 7.
Let us divide the second 3 digit number 101 by 7.
101/7 = 14.43
We have decimal in the result of 101/7 also.
So, the second 3 digit number 101 is also not exactly divisible by 7
The first 3 digit number is also 100.
To find the first 3 digit number divisible by 7, we divide the very first 3 digit number 100 by 7
100/7 = 14.29
We have decimal in the result of 100/7.
Clearly the first 3 digit number 100 is not exactly divisible by 7.
Let us divide the second 3 digit number 101 by 7.
101/7 = 14.43
We have decimal in the result of 101/7 also.
So, the second 3 digit number 101 is also not exactly divisible by 7
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