Find the sum of all three digit numbers divisible by 4 and 3.
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the numbers which are divisible by 4 and 3, is a multiple of 4*3 i.e.
they are multiple of 12.
the lowest 3 digit number which is divisible by 12 is 108.
the largest 3 digit number which is divisible by 12 is 83*12=996 [since 1000/12=83.33]
let the total number of 3 digit numbers which is divisible by 4 and 3 is n.
therefore 996=108+(n-1)*12
906-108=(n-1)*12
888=(n-1)*12
n-1=888/12=74
n=74+1=75
therefore the sum of the numbers which are divisible by 4 and 3 (i.e. divisible by 12) is

they are multiple of 12.
the lowest 3 digit number which is divisible by 12 is 108.
the largest 3 digit number which is divisible by 12 is 83*12=996 [since 1000/12=83.33]
let the total number of 3 digit numbers which is divisible by 4 and 3 is n.
therefore 996=108+(n-1)*12
906-108=(n-1)*12
888=(n-1)*12
n-1=888/12=74
n=74+1=75
therefore the sum of the numbers which are divisible by 4 and 3 (i.e. divisible by 12) is

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