Question

find the sum of all three digit numbers which are divisible by 5​

Answer 1

1.the first 3 digit no is 100 and last 3 digit no. is 995

2.total no. terms the is 180

3. between 100 and 200 there are 21 terms which are divisible by 5

4.201 to 300 there are 20 terms which are divisible by 5

5.so upto 800 to 900 20 terms are there which are divisible by 5

6. but in 900-1000 there are only 19 terms which are divisible by 5

7.so total terms=180

8.the terms are in AP so sum of n terms =n(a+l)/2

9.a=1st term and l is last term

10.so sum=180(100+995)/2=98500

11. so sum is 98500

Answer 2

Step-by-step explanation:

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