Question

find the sum of all three digit numbers which are divisible by 3 but not divisible by 5

Answer 1

333+333+333=999÷3=333&999÷5=199.9

so digit's are 333,333,333

Answer 2

Answer:

# include < stdio. h >

int main ( )

{

int i ,  

for ( i = 100 ; i<= 999 ; i++ )

{ if ( i % 3 == 0 && i % 5 != 0 ) // main logic

  printf ( " %d " , i ) ;

  sum = sum + i ;

}

printf ( " find the sum of all three digit numbers which are divisible by 3 but not divisible by 5  is % d " , sum ) ;

return 0 ;

}

note : if both condition is satisfied then the program will print the number and   lastly print the sum of all three digit numbers which are divisible by 3 but not divisible by 5