Math, asked by udayakumarich, 1 year ago

Find the sum of all three digit numbers which are divisible by 3 but not divisible by 5


salusuju: yaah please somebody answer this I also need this

Answers

Answered by RenatoMattice
14

Answer: The sum of all three digit numbers which are divisible by 3 but not divisible by 5 is 132300.

Step-by-step explanation:

Since we have given that

All three digit numbers which are divisible by 3 but not divisible by 5.

So, First we will write all the three digit numbers which are divisible by 3.

102,105,.....999

So, we will find the number of terms from 102 to 999.

a_n=a+(n-1)d\\\\999=102+(n-1)3\\\\999-102=3(n-1)\\\\897=3(n-1)\\\\\frac{897}{3}=n-1\\\\299=n-1\\\\n=300

And sum of all the above numbers is given by

S_{300}=\frac{n}{2}(a+a_n)=\frac{300}{2}(102+999)\\\\S_{300}=150\times (1101)\\\\S_{300}=165150

Now, we will find the series which are divisible by 3 and divisible by 5 i.e. divisible by 15.

105,120,........990

So, number of terms will be

a_n=a+(n-1)d\\\\990=105+(n-1)\times 15\\\\990-105=(n-1)\times 15\\\\885=(n-1)\times 15\\\\\frac{885}{15}=n-1\\\\59=n-1\\\\n=59+1=60

So, the sum will be

S_{60}=\frac{n}{2}(a+a_n)\\\\S_{60}=\frac{60}{2}(105+990)\\\\S_{60}=30(1095)\\\\S_{60}=32850

So, the sum of all three digit numbers which are divisible by 3 but not divisible by 5 is given by

165150-32850\\\\=132300

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