Question

find the sum of all three digit numbers which leaves remainder 1 when divided by 4​

Answer 1

Answer: 123525

Step-by-step explanation:

100 divided by 4 leaves remainder 0.

101 divided by 4 leaves remainder 1. So 101 is the lowest term.

999 divided by 4 leaves remainder 3.

997 divided by 4 leaves remainder 1. So 997 is the final term.

Let these are in AP.

So it will be like 101, 105, 109,......, 993, 997.

a = 101

a_n = 997

d = 4 (The divisor)

n = ((a_n - a)/d) + 1

n = ((997 - 101)/4) + 1

n = (896 / 4) + 1

n = 224 + 1

n = 225

S_n = n/2[a + a_n]

S_n = 225/2[101 + 997]

S_n = 225/2 × 1098

S_n = 225 × 549

S_n = 123525

Answer 2

Answer:ansis 123525

Step-by-step explanation: