Question

Find the sum of all three-digit numbers which when divided by 5 , yields 2 as remainder

Answer 1

Answer:

sum = 107910

Step-by-step explanation:

Sum series = n/2 [ 2a + ( n - 1) d]

n = total numbers in series = 900/ 5 = 180

a = first number in series = 102

d = difference between two numbers = 5

sum = 180/2 [ 2× 102 + ( 180 - 1 ) 5]

sum = 90 [ 204 + 199×5]

sum = 90 ( 204 + 995)

sum = 90 × 1199 = 107910

sum = 107910